关系模式 STJ(S#,T,J#)中,存在函数依赖: (S#,J#)→T,(S#,T)→J#,T→J#,则()
A、关系STJ满足3NF,但不满足BCNF;
B、关系STJ满足BCNF,但不满足4NF;
C、关系STJ满足2NF,但不满足3NF;
D、关系STJ满足1NF,但不满足2NF
发布时间:2025-05-22 05:35:18
A、关系STJ满足3NF,但不满足BCNF;
B、关系STJ满足BCNF,但不满足4NF;
C、关系STJ满足2NF,但不满足3NF;
D、关系STJ满足1NF,但不满足2NF